已知tan(a+β)=7,tana*tanβ=2/3则cos(a-β)=
人气:498 ℃ 时间:2020-05-19 23:21:27
解答
tan(a+β)=7(tana+tanβ)/(1-tanatanβ) = 73(tana+tanβ) = 73sin(a+β)/cosacosβ = 7cosacosβ= 3sin(a+β)/7= 3(7/5√2)/7= 3/(5√2) = 3√2/10 tanatanβ = 2/3sinasinβ/cosacosβ = 2/3sinasinβ = (2/3)cosa...
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