求积分∫（cos^2x/sin^2x）dx
人气：430 ℃ 时间：2020-04-09 03:05:22
解答
∫（cos^2x/sin^2x）dx
=积分((1-sin^2x)/sin^2xdx
=积分1/sin^2xdx-积分1dx
=积分csc^2xdx-x
==-cotx-x+C
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