答：1/(x+2)-1/(x+3)=1/(x+5)-1/(x+6)通分：[(x+3)-(x+2)]/[(x+2)(x+3)]=[(x+6)-(x+5)]/[(x+5)(x+6)]1/(x^2+5x+6)=1/(x^2+11x+30)所以：x^2+5x+6=x^2+11x+3011x-5x=6-306x=-24x=-4经检验,x=-4是原分式方程的根...