(√3+√2-√5)(√6+2+√10)
=(√3+√2-√5)×√2(√3+√2+√5)
=√2×[(√3+√2-√5)(√3+√2+√5)]
=√2×[(√3+√2)²-(√5)²]
=√2×(5+2√6-5)
=√2×2√6
=2√12
=4√3