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a2-3a+1=0,求a3+1/a3的值
人气:449 ℃ 时间:2020-05-22 03:55:53
解答
a2-3a+1=0
显然a=0不能满足要求,因此两边都除以a,
=>
a+1/a-3=0
=>a+1/a=3
a^2+1/a^2=(a+1/a)^2-2=3^2-2=7
a^3+1/a^3
=(a+1/a)(a^2+1/a^2-1)
=3*(7-1)
=18
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