已知a是方程x2+x-1=0的根
则a²+a-1=0;
a²+a=1;
则a3-a2-3a+1
=aˆ3+a²-2a²-3a+1
=a(a²+a)-2a²-3a+1
=a-2a²-3a+1
=-2a²-2a+1
=-2×1+1
=-1;
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