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计算题:1' (0.25)^-0.5+(1/27)^-(1/3)-625^0.25
2' a^15 ×a^(-15) ×(a^-5)^0.5 ×(a^0.5)^3 (a>0)
3' (0.064)^-(1/3) -(-7/8)^0 +[(-2)^3]^(-4/3)+16^-0.75
4’
(124+22√3 )^(1/2)-27^(1/6)+16^(3/4)-2×(8^-2/3)^- 1 +5√2 ×(4^-2/3)^-1
人气:142 ℃ 时间:2020-01-26 02:44:17
解答
1' (0.25)^-0.5+(1/27)^-(1/3)-625^0.25=(0.5)^-1+(1/3)^-1-5=2+3-5=02' a^15 ×a^(-15) ×(a^-5)^0.5 ×(a^0.5)^3 (a>0)=a^0 ×(a^0.5 )^-5×(a^0.5)^3 =(a^0.5 )^-2=a^-1=1/a3' (0.064)^-(1/3) -(-7/8)^...
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