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(-0.125)^2010*8^2009
(x+y-3)(x+y+3)
(2x-3)^2(2x+3)^2
人气:313 ℃ 时间:2020-04-12 01:08:12
解答
(-0.125)^2010*8^2009
=(0.125)^2010*8^2009
=8^(-2010)*8^2009
=8^(-1)
=1/8
(x+y-3)(x+y+3)
=(x+y)^2-9
(2x-3)^2(2x+3)^2
=[(2x+3)(2x-3)]^2
=(4x^2-9)^2
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