x²/a²+y²/b²=1一个焦点为F1(-√3,0)那么a²-b²=3①过点H(√3,1/2)所以3/a²+1/4b²=1②联立①②解方程组得a²=4,b²=1所以椭圆方程是x²/4+y²=1...怎样解方程？设x=b²(x＞0)那么a²=x+3所以3/(x+3)+1/4x=13*4x+x+3=4x(x+3)13x+3=4x²+12x4x²-x-3=0(x-1)(4x+3)=0x=1,x=-3/4(舍去)所以a²=x+3=4,b²=x=1