由x+4>0,x-1>0,x+8>0得x>1∵log2(x+4)+log2(x-1)=log2(2)+log2(x+8)∴log2(x+4)(x-1)=log2(x+8)*2,即(x+4)(x-1)=2(x+8)解得x=4,x=-5(舍去）∴log2(x+4)+log2(x-1)=1+log2(x+8)的解为：x=4