∵∫arcsinxdx/√(1-x²)=[(arcsinx)²]│-∫arcsinxdx/√(1-x²)(应用分部积分法) ==>2∫arcsinxdx/√(1-x²)=[(arcsinx)²]│(把∫arcsinxdx/√(1-x²)移项) ∴∫arc...