x2+y2-2x+6y+6=0.(x-1)^2 + (y+3)^2 = 4,圆心（1,-3）,半径=2因为“已知过点A(-1,-1)的直线L与圆x2+y2-2x+6y+6=0相交”,故圆心到该直线的距离 < 半径,设直线：y + 1 = k(x+1),kx-y+k-1 = 0,圆心到直线的距离= 2/k+1/...