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(4x-1)÷3-(x-2)÷6=(4+x)÷2 怎么解
(1)(4x-1)÷3-(x-2)÷6=(4+x)÷2 (2)x/3-x/5=4 (3)(y+2)÷4-(y-3)÷5=10
人气:390 ℃ 时间:2020-04-24 06:39:21
解答
(1)(4x-1)÷3-(x-2)÷6=(4+x)÷2 2(4x-1)-(x-2)=3(4+x)8x-2-x+2=12+3x4x=12x=3(2)x/3-x/5=4 5x-3x=602x=60x=30(3)(y+2)÷4-(y-3)÷5=105(y+2)-4(y-3)=2005y+10-4y+12=200y=178
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