原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(x-4)=[(x+2)(x-2)-x(x-1)]/x(x-2)² ×x/(x-4) =(x²-4-x²+x)/(x-2)²×1/(x-4) =1/(x-2)²当x=-3时原式=1/(...��ʵ��Χ����ʽ�ֽ⣺X��ƽ����5���ڣ�x²-5=x²-(��5)²=(x+��5)(x-��5) �����