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已知sin(x-y)=3/5,sin(x+y)=-3/5,且x属于(兀/4,兀/2),y属于(-3兀/4,-兀/2),求sin2x的值.
人气:387 ℃ 时间:2020-04-05 09:12:53
解答
解得:x∈(π/4,π/2),y∈(-3π/4,-π/2)∴x+y∈(-π/2,0),x-y∈(3π/4,5π/4)又∵sin(x-y)=3/5,sin(x+y)=-3/5∴cos²(x-y)=1-9/25=16/25cos²(x+y)=1-9/25=16/25∴cos(x-y)=-4/5,cos(x+y)=...
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