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(1)(5a-3a2+1)-(4a3-3a2);
(2)-2(ab-3a2)-[2b2-(5ab+a2)+2ab]
人气:210 ℃ 时间:2020-03-25 16:21:42
解答
(1)原式=5a-3a2+1-4a3+3a2=-4a3+5a+1.
(2)原式=-2ab+6a2-2b2+5ab+a2-2ab
=7a2-2b2+ab.
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