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2(lg2)^2+(lg5)^2+3lg2lg5-lg2=
人气:269 ℃ 时间:2020-04-20 07:59:16
解答
2(lg2)^2+(lg5)^2+3lg2lg5-lg2
=2(lg2)^2+2lg2lg5+(lg5)^2+lg2lg5-lg2
=2lg2(lg2+lg5)+lg5(lg5+lg2)-lg2
=2lg2+lg5-lg2
=lg2+lg5
=1
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