> 数学 >
(8x^3+8x^2+4x+1)(8x^3-8x^2+4x-1)
人气:182 ℃ 时间:2020-04-13 17:14:36
解答

(8x^3+8x^2+4x+1)(8x^3-8x^2+4x-1)
=[(8x^3+4x)+(8x^2+1)][(8x^3+4x)-(8x^2+1)]
=(8x^3+4x)^2-(8x^2+1)^2
=[(8x^3)^2+(4x)^2+2*32x^4]-[64x^4+1+2*8x^2]
=64x^6+16x^2+64x^4-64x^4-1-2*8x^2
=64x^6-1
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版