双曲线16x2-9y2=144即：x^2/9-y^2/16=1a^2=9,b^2=16c^2=a^2+b^2=25右焦点为：(5,0)一条渐近线斜率=b/a=4/3因此,过右焦点的平行线方程为：y=4(x-5)/3解方程组：y=4(x-5)/3x^2/9-y^2/16=1得：x=17/5,y=-32/15所以,交点...