二次型f(x1x2x3x4)=2x1x2+2x1x4+2x2x3+2x3x4 的秩为?
人气：336 ℃ 时间：2020-02-06 03:57:58
解答
A=
0 1 0 1
1 0 1 0
0 1 0 1
1 0 1 0
->
0 1 0 1
1 0 1 0
0 0 0 0
0 0 0 0
所以二次型的秩为2.
推荐
- 用配方法化标准二次型：f(x1,x2,x3,x4)=2x1x2+2x1x3+2x1x4+2x2x3+2x2x4+2x3x4
- 求一个正交变换,把实二次型f（x1,x2,x3）=2X1x2+2X1x3-2X1X4-2X2X3+2X2X4+2X3X4化为标准型
- 求实二次型f(x1,x2,x3,x4)=x1^2+x2^2+x3^2+x4^2+2x1x2-2x1x4-2x2x3+2x3x4的规范型
- 二次型f(x1,x2,x3)=2x1x2+2x2x3-4x1x3的矩阵A为
- 已知二次型f(x1,x2,x3,x4)=2x1x4+2x2x3,求二次型的秩
- Linda didn't find her handbag.She _____(put)it on the chair at the door but it was now not there.
- 在深度为1×10的四次方m的太平洋马里亚纳海沟,科学家发现有鱼游动.这些鱼受到海水压强是多少pa?
- 救人一命 胜造七级浮屠
猜你喜欢
