f'(x)=[3x^2(x-1)^2-2(x-1)*x^3]/(x-1)^4=x^2(x-3)/(x-1)^3,令f(x)=0.10,∴x∈（-∞,1）时单调增函数,10,单调增函数,∴x∈[3,+∞)时单调增函数,.f"(x)=6x/(x-1)^4,x=0,是拐点,x0,曲线向上凹,x=1是垂直渐近线....