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数学
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化简(1+sina2α)/(1+sin2α+cos2α)-(1/2)tanα
人气:335 ℃ 时间:2020-03-15 23:04:55
解答
(1+sin2α)/(1+sin2α+cos2α)-(1/2)tanα
=(sin²a+cos²a+2sinacosa)/(2sinacosa+2cos²a)-sina/(2cosa)
=(sina+cosa)²/[2cosa(sina+cosa)]-sina/(2cosa)
=(sina+cosa)/(2cosa)-sina/(2cosa)
=(sina+cosa-sina)/(2cosa)
=cosa/(2cosa)
=1/2.
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