(sin²α+tanα×tanα/2+cos²α)x(sin²α/2cosα)
=（1+tanα×tanα/2）x(sin²α/2cosα)
=（cosαcosα/2+sinαsinα/2)*(sinα/2)^2/(cosα/2)
=(sinα/2)^2
≠tanα,
请检查题目.