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(x+1)(x-1)(x²-x+1)(x²+x+1)计算 大根号 9-4根号5 化简 2x²+4x-3 分解因式
人气:399 ℃ 时间:2020-02-03 14:49:26
解答
(x+1)(x-1)(x²-x+1)(x²+x+1)
=(x+1)(x²-x+1)((x-1)(x²+x+1)
=(x^3+1)(x^3-1)
=x^6-1
√(9-4√5)
=√(2-√5)^2
=√5-2
2x²+4x-3
=2(x²+2x+1)-2-3
=2(x+1)²-5
=2[(x+1)²-(√10/2)²]
=2(x+1+√10/2)(x+1-√10/2)
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