1/(sin x+cos x) 的不定积分
人气:257 ℃ 时间:2020-01-31 17:02:36
解答
∫1/(sinx+cosx) dx
=∫1/[√2·(sinxcosπ/4+sinπ/4·cosx)]dx
=∫1/[√2·sin(x+π/4)] dx
=√2/2 ∫csc(x+π/4) d(x+π/4)
=√2/2 ln|csc(x+π/4)-cot(x+π/4)|+C
推荐
猜你喜欢
- 求离别情意的古诗词.越多越好
- What the soldier ( )good to our country A,does do B,does do does C,does does do D,do does do
- 望远镜是低倍看得远还是高倍看得远
- 倾听
- 一列火车通过一座长2.7米的大桥,从车头上桥到车尾离桥共需4分钟.已知火车的速度是每分钟0.8千米.这列火车长多少米?
- :已知抛物线y=ax的平方-2x+c的顶点为(1,-4)求a c的值.
- The story is very interisting.Will you please__it__us?A.read,for B.tell,for C.read,to D.say,to.应选
- 1.同一周期从左到右原子半径减小 2.非金属的原子半径<其阴离子的原子半径