(n+1)²+n²+n²(n+1)²=(n+1)²-2n(n+1)+n²+2n(n+1)+n²(n+1)²=[(n+1)-n]²+2n(n+1)+n²(n+1)²=1+2n(n+1)+n²(n+1)²=(1+n+n²)²通分原式=√{[(n...