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数学
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已知a,b∈R
求证:a^2 + b^2 + a*b +1 > a + b
人气:455 ℃ 时间:2020-08-27 23:12:37
解答
简而言之,先将右边的a+b移到左边然后将a^2 b^2分别进行配方得出(a-1)^2和(b-1)^2这时会剩下+ab+a+b-1,以下将管这部分叫做零碎此时的式子为“(a-1)^2+(b-1)^2+ab+a+b-1”这个式子标号为式子①然后对式子①进行变...
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