三元一次方程求解：x+2z=3,2x+y=2,2y+z=7
要用代入法,
人气：317 ℃ 时间：2019-09-29 16:07:14
解答
1.x+2z=3 ①
2x+y=2 ②
2y+z=7 ③
将①×2-②,得4z-y=4 ④
将④×2+③,9z=15,z=5/3
将z=5/3代入③式,得2y+5/3=7,y=8/3
将y=8/3代入②,得2x+8/3=2,x=-1/3
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