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已知m^2-5m-1=0,则2m^2-5m+(1/m^2)
人气:166 ℃ 时间:2020-06-12 12:50:32
解答
m^2-5m-1=0m≠0,两边同除以m,得m-1/m=5(m-1/m)²=25m²+1/m²-2=25m²+1/m²=27m^2-5m=12m^2-5m+(1/m^2)=m²+m²-2m+(1/m²)=m²+(1/m²)+1=27+1=28m²+1/m²-2=25m²+1/m²=2323应该改为27吧!
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