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证明tanθ×((1-sinθ)/(1+cosθ))=cotθ×((1-cosθ)/(1+sinθ))
人气:186 ℃ 时间:2019-09-29 05:50:58
解答
tanθ[(1-sinθ)/(1+cosθ)][(1+sinθ)/(1-cosθ)]
=tanθ([1-(sinθ)^2]/[1-(cosθ)^2])
=tanθ[(cosθ)^2)/(sinθ)^2)]
=(sinθ/cosθ)[(cosθ)^2)/(sinθ)^2)]
=cosθ/sinθ
=cotθ
即得tanθ[(1-sinθ)/(1+cosθ)]=cotθ[(1-cosθ)/(1+sinθ)]
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