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因式分解 (x²-1)(x+3)(x+5)+16
人气:415 ℃ 时间:2020-04-15 02:16:04
解答
(x²-1)(x+3)(x+5)+16=(x+1)(x+3)(x-1)(x+5)+16=(x^2+4x+3)(x^2+4x-5)+16
=(x^2+4x)^2-2(x^2+4x)+1=(x^2+4x-1)^2
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