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y=ln(1+x^2)的二阶导数,
人气:339 ℃ 时间:2020-02-03 00:27:58
解答
y' = (1+x²)'/(1+x²) = 2x/(1+x²)
y" = [(1+x²)(2x)' - (1+x²)'(2x)/(1+x²)²
= 2(1-x²)/(1+x²)²
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