y=ln(1+x^2)的二阶导数,_数学解答

y=ln(1+x^2)的二阶导数,

人气：291 ℃　时间：2020-02-03 00:27:58

解答

y' = (1+x²)'/(1+x²) = 2x/(1+x²)
y" = [(1+x²)(2x)' - (1+x²)'(2x)/(1+x²)²
= 2(1-x²)/(1+x²)²