如图所示BP平分∠ABC交CD于F,DP平分∠ADC交AB于E,DP、BP交于P,AB与CD相交于O.若∠A=40°,∠C=36°,求∠P的度数.BP平分∠ABC交CD于F,DP平分∠ADC交AB于E,DP、BP交于P,AB与CD相交于O.若∠A=40°,∠C=36°,求∠P的度数.我要的是过程,准确的.答案是38°.
人气：322 ℃ 时间：2020-09-19 22:17:51
解答
设∠ADP＝∠1,∠ABP＝∠2∵BP平分∠ABC∴∠ABC＝2∠2∴∠AOC＝∠C+∠ABC＝∠C+2∠2∵DP平分∠ADC∴∠ADC＝2∠1∴∠AOC＝∠A+∠ADC＝∠A+2∠1∴∠A+2∠1＝∠C+2∠2∴2（∠1-∠2）＝∠C-∠A∵∠AEP＝∠A+∠1,∠AEP＝∠...
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