方程:已知x加y等于105,3/8x加4/7y等于49,问x和y分别是多少?
人气:186 ℃ 时间:2020-02-06 05:58:09
解答
x+y=105
y=105-x
代入(3/8)x+(4/7)y=49
(3/8)x+(4/7)(105-x)=49
(3/8-4/7)x+105*4/7=49
-(11/56)x+60=49
(11/56)x=11
x=56
y=105-x=49
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