sina cosp=1/2,则cosa sinp范围
人气:320 ℃ 时间:2020-06-29 07:53:50
解答
(cosa sinp)²=(1-sin²a)(1-cos²p)
=(1-(sin²a+cos²p)+in²acos²p)
=(5/4-(sin²a+cos²p))
≤(5/4-2√(sin²acos²p)
=(5/4-1)
=1/4
即(cosa sinp)²≤1/4
-1/2≤cosa sinp≤1/2
推荐
- 已知向量a=(cosa,sina),b=(cosp,sinp)且a,b满足│ka+b│=根号3│a-kb│求K的取值范围?
- 已知sina+sinp=½ cosa+cosp=1╱3则cos(a-p)等于
- 化简1.sin(a+p)cosa-cos(a+p)sina 2.sin(a-p)cosp+cos(a-p)sinp
- sina+sinp=根号3/3(cosp-cosa),且a、p都属于第一二象限,则a-p=
- sina>cosa,sina
- 3a三次方—12a平方+12a分解因式
- I live with my mum,dad and grandma in a small honse in Edinburgh,in the north of England.
- 一个长方体游泳池长60米,宽30米,深2米,游泳池的占地面积是多少平方米?沿游泳池的内壁1.5米处用红
猜你喜欢