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sina cosp=1/2,则cosa sinp范围
人气:320 ℃ 时间:2020-06-29 07:53:50
解答
(cosa sinp)²=(1-sin²a)(1-cos²p)
=(1-(sin²a+cos²p)+in²acos²p)
=(5/4-(sin²a+cos²p))
≤(5/4-2√(sin²acos²p)
=(5/4-1)
=1/4
即(cosa sinp)²≤1/4
-1/2≤cosa sinp≤1/2
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