已知向量a=cos,sin若a=,求函数的最小值
人气:191 ℃ 时间:2020-06-12 20:52:48
解答
这题不错,够16分:
1
α=π/4,即:c=(sinx+√2,cosx+√2)
f(x)=b·c=(cosx,sinx)·(sinx+√2,cosx+√2)
=sin(2x)+√2(sinx+cosx)
=sin(2x)+2sin(x+π/4)
=-cos(2x+π/2)+2sin(x+π/4)
=-(1-2sin(x+π/4)^2)+2sin(x+π/4)
=2sin(x+π/4)^2+2sin(x+π/4)^2-1
=2(sin(x+π/4)+1/2)^2-3/2
0
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