帮忙换底化简下列:logaC*logcA .log2 3 * log3 4 * log4 5 * log5 2_数学解答

帮忙换底化简下列:logaC*logcA .log2 3 * log3 4 * log4 5 * log5 2

人气：293 ℃　时间：2019-10-17 03:12:54

解答

1、logaC×logcA= logaC×(1/logaC)=1
2、log2 3 × log3 4 × log4 5 × log5 2
=[1/(log3 2)]×2log3 2×[1/(log5 4)]×log5 2
=2×[1/2(log5 2)]×log5 2
=2×(1/2)
=1