两边乘以CX 得到 cx²+mc=c²x+mxcx²-(c²-m)+mc=0(cx-m)(x-c)=0∴x=m/c 或x=c检验：把x=c代入方程得左边=c+m/c 右边=c+m/c 所以x=c是方程的解同理：把x=m/c代入方程得左边=m/c+c=c+m/c 右边=c+m/c...x+2/x-1=a+2/a-1同样求过程x+2/x-1=a+2/a-1x-a+2/(x-1)-2/(a-1)=0(x-a)+2(a-1-x+1)/(x-1)(a-1)=0(x-a)-2(x-a)/(x-1)(a-1)=0(x-a)[1-2/(x-1)(a-1)]=0x=a2/(x-1)(a-1)=1(x-1)(a-1)=2x-1=2/(a-1)x=1+2/(a-1)=(a+1)/(a-1)所以x=a,x=(a+1)/(a-1)x+2/x-1=a+2/a-1x-a+2/(x-1)-2/(a-1)=0 这步怎么隔清楚?x-a+2/(x-1)-2/(a-1)=0 那个是单独的一个数 哪个是分子上面给你分出来了。。我只是把左边的移动到右边式子等于0 来化简