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(3/2x方+xy-3/5y方)*(-4/3x方y方)
人气:336 ℃ 时间:2020-10-01 11:12:26
解答
(3/2x²+xy-3/5y²)×(-4/3x²y²)
=3/2x²*(-4/3x²y²)+xy*(-4/3x²y²)-3/5y²*(-4/3x²y²)
= -2x^4y^2-4/3x^3y^3+4/5x^2y^4
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