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求lim(n->0){(sin(n/2))/n},
人气:456 ℃ 时间:2020-05-21 23:54:33
解答
用洛必达法则,上下求导
lim(n->0){(sin(n/2))/n}
=lim(n->0){(1/2)cos(n/2))/1}
=1/2
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