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若(2x+y-1)²+|x-2y-3|=0,求代数式(3x+y)(3x-y)-(x+2y)(x-y)-3的值
已知a+1/a=5,求a-1/a的值
人气:285 ℃ 时间:2019-10-19 02:26:24
解答
2x+y-1=0
x-2y-3=0
x=1
y=-1
(3x+y)(3x-y)-(x+2y)(x-y)-3
=2*4+1*2-3
=8+2-3
=7
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