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计算:1+(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+…(1/1+2+3+…2009+2010)
括号内是一个整体分数。我不会打分数线,分子都是1,分母是(1+2+3+4+…)到2010请谅解!
人气:124 ℃ 时间:2019-09-22 05:13:35
解答
=1+(1/3+1/6)+(1/10+1/15)+(1/21+1/28)+…+(1/(2009*1004)+1/(2009*2005))+1/(2011*1005)
=1+1/(1*2)+1/(2*3)+1/(3*4)+…+1/(1004*1005)+1/(2011*1005)
=1+1-1/2+1/2-1/3+1/3-1/4+…+1/1004-1/1005+1/(2011*1005)
=1+1-1/1005+1/(2011*1005)
=2-2011/(2011*1005)+1/(2011*1005)
=2-2010/(2011*1005)
=4020/2011
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