a=2,b=-(4m-1),c=-m^2-m
△=b^2-4ac
=[-(4m-1)]^2-4x2x(-m^2-m)
=16m^2+1-8m+8m^2+8m
=24m^2+1
∵24m^2+1的值恒大于0
∴△＞0
故：不论m为何值,方程总有两个不相等的实数根