∠BAC < ∠BPC,∠ABC < ∠APC理由：延长AP ,设交BC于D.∠BPD = ∠BAP + ∠ABP,所以 ∠BPD 〉∠BAP ∠DPC = ∠DAC + ∠ACP,所以 ∠DPC 〉∠DAC所以∠BPC= ∠BPD + ∠DPC 〉 ∠BAP + ∠DAC=∠BAC 同理,∠ABC < ∠APC...