a的2次+b的2次-2a+6b+10=0
[a^2-2a+1]+[b^2+6b+9]=0
[a-1]^2+[b+3]^2=0
a-1=0
b+3=0
a=1
b=-3
b^a=(-3)^1=-3
记得采纳回答哦~