定义域为x>0在定义域单调增,即f'(x)>=0恒成立f'(x)=a+(1-lnx)/x^2>=0a>=(lnx-1)/x^2=g(x)现求g(x)的最大值.由g'(x)=[x-2x(lnx-1)]/x^4=(3-2lnx)/x^3=0,得极值点x=e^(3/2)此为极大值点,也是最大值点g(e^(3/2))=1/(2e^...