这个式子是怎么化简出来的
x/(x^2+1)-y/(y^2+1)=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)]我算了很多次我只能化成[(x-y)(x^2+y^2+1)]/[(x^2+1)(y^2+1)]而已
人气：410 ℃ 时间：2020-06-24 11:56:37
解答
=[y^2*x+x-y-x^2*y]/[(x^2+1)(y^2+1)]
=[(x-y)+xy(y-x)}/[(x^2+1)(y^2+1)]
=[(x-y)-xy(x-y)]/[(x^2+1)(y^2+1)]
=[(x-y)(1-xy)]/[(x^2+1)(y^2+1)]
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