找规律:
(1—1/2)*(1+1/2)*(1—1/3)*(1+1/3)*(1—1/4)*(1+1/4)=
有什么规律?
人气:209 ℃ 时间:2020-03-28 18:49:00
解答
(1—1/2)*(1+1/2)*(1—1/3)*(1+1/3)*(1—1/4)*(1+1/4)=1/2×3/2×2/3×4/3×3/4×5/4=5/8(1—1/2)*(1+1/2)*(1—1/3)*(1+1/3)*(1—1/4)*(1+1/4)×……×(1-1/n)(1+1/n)=(n+1)/(2n)...
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