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cos150°×cos(-570°)×tan(-330°)/cos(-420°)×sin(-690°)
人气:335 ℃ 时间:2020-05-26 20:15:23
解答
cos150°×cos(-570°)×tan(-330°)/cos(-420°)×sin(-690°)
=-cos30°×cos210°×tan(-30°)/cos60°×sin30°
=-√3/2×(-√3/2)×(-√3/3)/(1/2×1/2)
=3/4×(-√3/3)×4=-√3
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