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求值[tan(-330)cos(-570)cos150sin(-420)]/[cos(-420)sin(-690)]
人气:360 ℃ 时间:2020-06-06 08:29:51
解答
[tan(-330)cos(-570)cos150sin(-420)]/[cos(-420)sin(-690)]=[tan(-360+30)cos(-720+150)cos150sin)]/[cos(-360-60)sin(-720+30)](360度整倍数直接拿出)=[tan(30)cos(150)cos150sin(-60)]/[cos(-60)sin(30)]= -[tan...
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